Protect Companion + Called Shot

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Rocmistro
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Re: Protect Companion + Called Shot

Post by Rocmistro » Wed Aug 20, 2014 1:43 pm

Just to preserve my own interwebz dignity, I did know the maths I originally posted were offs. But I confess I didn't know what the correct maths formulez were, and I didn't care too much. :-)
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bluejay
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Re: Protect Companion + Called Shot

Post by bluejay » Wed Aug 20, 2014 2:34 pm

Absolutely and the main point still stands. I just felt that the 5/6 probability made it sound like it happened nearly all the time whereas in reality it's less than 2 shots out of 3. Personally I feel that makes called shot a little less attractive and so it is relevant.
James Semple, occasional composer of role playing music

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Rocmistro
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Re: Protect Companion + Called Shot

Post by Rocmistro » Wed Aug 20, 2014 2:46 pm

bluejay, just out of curiousity, what's the probability when you have 6 attack dice?
Rignuth: Barding Wordweaver Wanderer in Southron Loremaster's game.
Amroth Ol'Hir: High Elf Vengeful Kin Slayer in Zedturtle's game.
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zedturtle
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Re: Protect Companion + Called Shot

Post by zedturtle » Wed Aug 20, 2014 3:03 pm

Rocmistro wrote:bluejay, just out of curiousity, what's the probability when you have 6 attack dice?
Not Bluejay, but 66.5%

I was recently looking at this math, for a different thing where the chance of getting a 6 on 5 dice would trigger something special, so that's why it's fresh in the mind.

And, your approximation earlier was good enough for a gut feeling thing.
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bluejay
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Re: Protect Companion + Called Shot

Post by bluejay » Wed Aug 20, 2014 3:08 pm

:) Funny you should say that ... I was going to ask what you'd have written if you had 6 success dice.

Basically the maths is like this...

You calculate the chance that you don't roll a 6 on every dice and then subtract that probability from 1.

So for each dice there is a 5/6 chance of not rolling 6. For multiple conditions that have to occur you multiply the probability. So for 1 dice the chance of not rolling 6 is 5/6. For 2 dice the chance of not rolling 6 on either dice is 5/6 x 5/6. You could write this as (5/6)^2.

Therefore the chance of rolling at least one six on n dice is

1 - (5/6)^n

For the specific case you asked (6 dice) the probability of rolling at least 1 six is: -

1 - (5/6)^6 which is around 66.5%

Hope that helps! Probability isn't even intuitive for me and my degree was Mathematics! :)
James Semple, occasional composer of role playing music

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